Solution:
We want to solve the given triangle;
[tex]\begin{gathered} cos\angle G=\frac{h^2+i^2-g^2}{2ih} \\ =0.9029 \\ \angle G=cos^{-1}0.9029=25.46^o \end{gathered}[/tex][tex]\begin{gathered} cos\angle H=\frac{g^2+i^2-h^2}{2gi} \\ =0.5 \\ H=cos^{-1}0.5=60^o \end{gathered}[/tex]
Thus;
[tex]\angle I=180-60-25.46=94.54^o[/tex]
Thus the full measures of the triangle are;
[tex]\begin{gathered} g=6.9,h=13.9,i=16.0 \\ \angle G=25.46^o,\angle H=60^o,\angle I=94.54^o \end{gathered}[/tex]
