Given:
[tex]m^3-49m[/tex]
To factorise:
Let us take the common factor outside the bracket.
[tex]\begin{gathered} m^3-49m=m(m^2-49) \\ =m(m^2-7^2) \end{gathered}[/tex]
Using the algebraic identity,
[tex]a^2-b^2=(a+b)(a-b)[/tex]
We can write,
[tex]=m(m+7)(m-7)[/tex]
Final answer:
The factored form,
[tex]m(m+7)(m-7)[/tex]
