Given data:
* The acceleration of the runner is,
[tex]a=3.2ms^{-2}[/tex]* The initial velocity of the runner is,
[tex]u=9.23ms^{-1}[/tex]* The time given is,
[tex]t=6.7s[/tex]Solution:
By the kinematics equation, the final velocity of the runner is,
[tex]v-u=at[/tex]where v is the final velocity,
Substituting the known values,
[tex]\begin{gathered} v-9.23=3.2\times6.7 \\ v-9.23=21.44 \\ v=21.44+9.23 \\ v=30.67ms^{-1} \end{gathered}[/tex]Thus, the final velocity of the runner is 30.67 m/s.
