Respuesta :
Answer:
68.18 L of 16% acid solution and 31.82 L of 60% acid solution
Explanation:
Let the number of liters of 16% acid solution be a
Let the number of liters of 60% acid solution be b
The sum of both will give the 100
Mahematically, we can write this as follows;
[tex]a\text{ + b = 100}[/tex]Secondly, if we multiply each concentration by the number of liters and sum it up, it will be equal to the total concentration multiplied by its number of liters
Kindly note that 16% = 16/100 = 0.16
60% = 60/100 = 0.6
30% = 30/100 = 0.3
Thus, we have it that:
[tex]\begin{gathered} 0.16a\text{ + 0.6b = 100(0.3)} \\ 0.16a\text{ + 0.6b = 30} \end{gathered}[/tex]Now, we have two equations to solve simultaneously
From equation 1:
[tex]a\text{ = 100-b}[/tex]Substitute this into equation ii
[tex]\begin{gathered} 0.16(100-b)\text{ + 0.6b = 30} \\ 16-0.16b\text{ + 0.6b = 30} \\ 0.6b-0.16b\text{ = 30-16} \\ 0.44b\text{ = 14} \\ b\text{ = }\frac{14}{0.44} \\ b\text{ = 31.82 L} \end{gathered}[/tex]Finally, we can get a from susbtituting the value of b into the first equation
Mathematically, we have this as:
[tex]\begin{gathered} a\text{ = 100-b} \\ a\text{ = 100-31.82} \\ a\text{ = 68.18 L} \end{gathered}[/tex]