Okay, here we have this:
Considering the provided quadratic function, we are going to rewrite in standard form, so we obtain the following:
So to rewrite the function in standard form we will complete the square:
[tex]\begin{gathered} x^2-8x \\ =x^2-8x+(-4)^2-(-4)^2 \\ =(x-4)^2-(-4)^2 \\ g(x)=(x-4)^2-16 \end{gathered}[/tex]
And from this equation we get that the vertex is (4, -16)
Therefore the correct graph is the one in the upper right corner.
