The shortest distance from D to B is the line that forms two square triangles on the top of the box:
Then, our problem narrows to find the length of x which is done by using the Pythagoras Theorem:
[tex]\begin{gathered} x^2=8^2+15^2 \\ x=\sqrt[]{64+225} \\ x=\sqrt[]{289} \\ x=17 \end{gathered}[/tex]
Therefore, the distance between D and B is 17 m
