Explanation:
To figure out the value of sin 28, we will use the trigonometric ratio below
[tex]\begin{gathered} sin\theta=\frac{opposite}{hypotenus} \\ where, \\ opposite=8 \\ hypotenus=17 \\ \theta=28^0 \end{gathered}[/tex]
By substituting the values, we will have
[tex]\begin{gathered} s\imaginaryI n\theta=\frac{oppos\imaginaryI te}{hypotenus} \\ sin28^0=\frac{8}{17} \end{gathered}[/tex]
Hence,
The final answer is
[tex]\Rightarrow s\imaginaryI n28^0=\frac{8}{17}[/tex]
OPTION F is the right answer
