Given,
The length of the pipe, L=45.132 cm=0.45132 m
The speed of the sound is v=343 m/s
The frequency of the 1 st harmonic is given by,
[tex]f_1=\frac{v}{2L}[/tex]
On substituting the known values,
[tex]\begin{gathered} f_1=\frac{343}{2\times0.45132} \\ =378\text{ Hz} \end{gathered}[/tex]The frequency of the second harmonic is given by,
[tex]f_2=2f_1[/tex]On substituting the known values,
[tex]\begin{gathered} f_2=2\times378 \\ =756\text{ Hz} \end{gathered}[/tex]The frequency of the third harmonic is given by,
[tex]f_3=3f_1[/tex]On substituting the known values,
[tex]\begin{gathered} f_3=3\times378 \\ =1134\text{ Hz} \end{gathered}[/tex]Therefore the frequency of 1st harmonic is 378 Hz.
The frequency of the 2nd harmonic is 765 Hz
The frequency of the 3rd harmonic is 1134 Hz
