[tex]\begin{gathered} \text{The formula is,} \\ A=P(1+R)^t \\ \text{Here, A is the final number} \\ \text{P is the initial number} \\ R\text{ is the rate } \\ t\text{ is the time} \\ \text{Then,} \\ A=100(1+\frac{22}{100})^8 \\ A=100\times1.22^8 \\ A=491\text{ frogs after 8 years} \end{gathered}[/tex]
