contestada

A lawn mower runs on a mixture of gas and oil the ratio of ounces of gas to ounces of oil is 32 to 1 how many ounces of oil does the lawn mower need for 96 oounces of gas

Respuesta :

Since the ratio of ounces of gas to oil is 32 to 1, we can solve the question by the rule of three.

[tex]\begin{gathered} 32\rightarrow1 \\ 96\rightarrow x \end{gathered}[/tex]

Then

[tex]\begin{gathered} x=\frac{96\cdot1}{32} \\ =\frac{96}{32} \\ =3 \end{gathered}[/tex]

Therefor, the lawn mower needs 3 ounces of oil.

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