we are to solve for x in
[tex]\text{ x}^{3\text{ }}+\text{ 1 = 9}[/tex]solving the eqaution
[tex]\begin{gathered} x^3\text{ + 1 = 9} \\ x^3\text{ = 9 - 1} \\ x^3\text{ = 8} \\ taking\text{ cube of both sides } \\ x\text{ = }\sqrt[3]{8} \\ x\text{ = 2} \end{gathered}[/tex]Hence, the value of x = 2
