y=2
[tex]\lbrack0,1)\text{ }\cup\text{ (3,4}\rbrack[/tex]
[tex]\begin{gathered} so,\text{ the function is negative in } \\ (1,3) \end{gathered}[/tex]
Explanation
Step 1
The y -intercept of a graph is the point where the graph crosses the y -axis.
so , let's check the graph
therefore, the y-intercept is 2
Step 2
The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero)
hence, the function is potive in ( in x axis)
[tex]\lbrack0,1)\text{ }\cup\text{ (3,4}\rbrack[/tex]
Step 3
negative region
The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero).
[tex]\begin{gathered} so,\text{ the function is negative in } \\ (1,3) \end{gathered}[/tex]
I hope this helps you
