Given:
[tex]\begin{gathered} Slope=-6/5 \\ y-intercept=2 \end{gathered}[/tex]To find:
The point-slope form of the equation.
Explanation:
The general point-slope form of the equation is,
[tex]y=mx+c[/tex]Substituting m = -6/5 and c = 2, we get
[tex]y=-\frac{6}{5}x+2[/tex]Therefore, the equation of the line in the point-slope form is,
[tex]y=-\frac{6}{5}x+2[/tex]Final answer:
The equation of the line in the point-slope form is,
[tex]y=-\frac{6}{5}x+2[/tex]