Respuesta :

[tex](\frac{3}{5})^8\times(\frac{9}{25})^2[/tex][tex](\frac{3}{5})^8\times(\frac{3^2}{5^2})^2[/tex][tex](\frac{3}{5})^8\times(\frac{3}{5})^{2\times2}[/tex][tex](\frac{3}{5})^8\times(\frac{3}{5})^4[/tex][tex](\frac{3}{5})^{8+4}[/tex][tex]=(\frac{3}{5})^{12}[/tex]

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