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Consider the point:(r,θ)=(6,−7).On the graph below, drag the purple point to the location (6,−7), and then select the equivalent representations of the point from the provided list.Equivalent polar representations of (r,θ)=(6,−7):(−6,−7−2π)(−6,−7+2π)(6,−7+2π)(−6,7)(6,−7−2π)

Consider the pointrθ67On the graph below drag the purple point to the location 67 and then select the equivalent representations of the point from the provided class=

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Answer:

Equilvalent representatins:

[tex]\begin{gathered} (6,-7+2\pi) \\ (6,-7-2\pi) \end{gathered}[/tex]

Explanation:

The equivalent point is found by adding or subtracting 2pi radians from the angle since a full revolution brings a point back where it was.

Therefore, we add and subtract 2pi from the radians to get

(6, -7 + 2 pi)

(6, -7 - 2pi )

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