Explanation:
-5x to the 2nd powe is: (-5x)² = (-5)²x² = 25x²
y to the 4th power is: y⁴
3xy to the 3rd power is: (3xy)³ = 3³ x³ y³ = 27 x³ y³
The product of all these expressions is:
[tex](-5x)^2\cdot y^4\cdot(3xy)^3=25\cdot x^2\cdot y^4\cdot27\cdot x^3\cdot y^{3}[/tex]We have to group like factors:
[tex](-5x)^2\cdot y^4\cdot(3xy)^3=(25\cdot27)\cdot(x^2\cdot x^3)\cdot(y^4\cdot y^{3})[/tex]And solve
[tex]\begin{gathered} (-5x)^2\cdot y^4\cdot(3xy)^3=(675)\cdot(x^{2+3})\cdot(y^{4+3}) \\ (-5x)^2\cdot y^4\cdot(3xy)^3=(675)\cdot(x^5)\cdot(y^7) \end{gathered}[/tex]Answer:
The answer is 675 x⁵ y⁷
