Answer:
The temperature change is 96.97°C.
Explanation:
The given information from the exercise is:
- Mass (m): 150g
- Specific heat of mercury (c): 0.0330cal/g.°C
- Heat (q): 480cal
To calculate the temperature change (ΔT) it is necessary to use the Heat formula, and replace the values of mass, specific heat and heat:
[tex]\begin{gathered} q=m*c*\Delta T \\ 480cal=150g*0.0330\frac{cal}{g*°C}*\Delta T \\ 480cal=4.95\frac{cal}{°C}*\Delta T \\ \frac{480cal}{4.95\frac{cal}{°C}}=\Delta T \\ 96.97\degree C=\Delta T \end{gathered}[/tex]So, the temperature change is 96.97°C.
