Answer:
Explanation:
Given:
[tex]y\text{ = log x}[/tex]
To find:
a) the values of y for the given x values
b) Graph the values
To determine the y values, we will substitute the values of x into the given function:
when x = 1
y = log 1 = 0.000 (3 d.p)
when x = 2
y = log 2 = 0.301 (3 d.p)
when x = 5.5
y = log 5.5 = 0.740
when x = 9
y = log 9 = 0.954
