Given the triangle below, find the correct value of the six trigonometric functions

Chek below, please.
1) Examining that triangle, we can state that this is a Pythagorean Triple therefore, that hypotenuse is 5
[tex]\begin{gathered} a^2=3^2+4^2 \\ a^2=9+16 \\ a^2=25 \\ a=5 \end{gathered}[/tex]2) So now, we can write out the following trig ratios, considering the acronyms for these trig ratios:
0. sin(θ) = Opposite/hypotenuse
,1. cos(θ) = adjacent/hypotenuse
,2. tan(θ)=opposite/adjacent
,3. csc(θ)=1/sin(θ)
,4. sec(θ)=1/cos(θ)
,5. cot(θ)=1/tan(θ)
3) So, the answer is: