Triangle ABC is graphed on the coordinate plane. What is the perimeter of ∆ABC? Enter your answer as the number only.

ANSWER:
30 units
STEP-BY-STEP EXPLANATION:
We can determine the perimeter which is the sum of all the sides of the triangle.
Side AB is 5 units. (3 + 2, we can see it in the graph)
Side BC is 12 units. (6 + 6, we can see it in the graph)
While we calculate side AC by means of the Pythagorean theorem, like this;
[tex]\begin{gathered} h^2=a^2+b^2 \\ \\ \text{ we replacing } \\ \\ AC^2=5^2+12^2 \\ \\ AC=\sqrt{25+144}=\sqrt{169} \\ \\ AC=13 \end{gathered}[/tex]Therefore, the perimeter would be:
p = 5 + 12 + 13
p = 30 units