A bag of 11 marbles contains 5 marbles with red on them, 4 with blue on them 5with green on themand 3 with red and green on them What is the probability that a randomly chosen marble has either green or red on it? Note that these events are not mutually exclusive Express your answer as a fraction in lowest terms or a decimal rounded to the nearest

Respuesta :

Explanation:

Step-by-step explanation:

Let's denote the events as follows:

R = a red marble is chosen

G = a green marble is chosen

The information provided is:

[tex]\begin{gathered} n(R)=5 \\ n(G)=5 \\ n(R\cap G)=3 \end{gathered}[/tex]

Total number of marbles in the bag is,

[tex]n(S)=11[/tex]

The probability of an event E is:

[tex]\begin{gathered} Pr(E)=\frac{n(E)}{n(S)} \\ Pr(R\cup G)=Pr(R)+Pr(G)-Pr(R\cap G) \\ Pr(R\cup G)=\frac{5}{11}+\frac{5}{11}-\frac{3}{11} \\ Pr(R\cup G)=\frac{7}{11} \end{gathered}[/tex]

Hence,

The final answer is

[tex]\frac{7}{11}[/tex]