A plane is flying to Minnesota with a velocity of 434.21 km/h, North.
The plane encounters a crosswind with a velocity of 93.07 km/h, West.
We are asked to find the magnitude of the resultant velocity of the plane.
Let us draw a diagram to better understand the problem.
The magnitude of the resultant velocity of the plane is given by
[tex]\begin{gathered} |v|=\sqrt[]{434.21^2+93.07^2} \\ |v|=\sqrt[]{188538.3241+8662.0249} \\ |v|=\sqrt[]{197200.349} \\ |v|=444.07\; \; \frac{m}{s} \end{gathered}[/tex]Therefore, the magnitude of the resultant velocity of the plane is 444.07 m/s
