Answer:
0.1975 probability of no 2 and no 3.
Step-by-step explanation:
The die is rolled four times.
A probability is the number of desired outcomes divided by the number of total outcomes.
Each time the dice is rolled, there are 6 possible values. 4 of them(those which are not 2 or 3) are desired.
So in one roll of the dice: 4/6 probability of no 2 and no 3.
In four rolls:
Each one with a 4/6 probability of no 2 and no 3.
[tex]p=(\frac{4}{6})^4=0.1975[/tex]0.1975 probability of no 2 and no 3.
