In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
a = 1
b= -2
Step 02:
[tex]\frac{a^{-3}}{2a^{-2}b^3}=\frac{1^{-3}}{2\cdot(1)^{-2}\cdot(-2)^3}^{}[/tex][tex]\frac{1^{-3-(-2)}}{2\cdot(-2)^3}=\frac{1^{-1}}{-16}=\frac{-1}{16}[/tex]
The answer is:
- 1 / 16
