Solution
Given the function 6x +3
[tex]\begin{gathered} \text{Let y = 6x + 3} \\ Replace\text{ x with y} \\ x\text{ =6y+3} \\ solve\text{ for y} \\ 6y\text{ =x-3} \\ \text{Divide both sides by 6} \\ y=\frac{x\text{ - 3}}{6} \\ \end{gathered}[/tex]
Hence,
[tex]f^{-1}(x)\text{ =}\frac{x-3}{6}[/tex]
