A plan for a garden is drawn in the coordinate plane. The garden is in the shape of a trapezoid. Each unit in the coordinate plane represents 1 foot what is the total area of the garden?

Respuesta :

Answer:

It is given that,

The garden is in the shape of a trapezoid

From the given figure,

The length of the bottom of the trapezoid,

[tex]=10-(-10)[/tex][tex]=10+10=20[/tex]

The length of the bottom of the trapezoid is 20 feet

The length of the top of the trapezoid is,

[tex]=6-(-6)=12[/tex]

The length of the two parallel sides of the trapezoid are 20 feet and 12 feet.

To find the height of the trapezoid

Height of the trapezoid is,

[tex]=2-(-4)=2+4=6[/tex]

Height of the trapezoid is 6

To find the area of the trapezoid

we know that,

Area of the trapezoid is

[tex]=\frac{1}{2}\times(a+b)\times(h)[/tex]

where a and b are the paralell sides of the trapezoid and h is the height of the trapezoid.

Substitute the values we get,

Area of the trapezoid is

[tex]=\frac{1}{2}\times(20+12)\times6[/tex][tex]=\frac{1}{2}\times32\times6=96[/tex]

Area of the trapezoid is 96 feet.