SOLUTION
When two dice of 6 faces are rolled together, the total number of outcome is
[tex]6\times6=36\text{ }[/tex]
That is 36 outcomes
Among these 36 outcomes, there are two outcomes that are greater than 3 and less than 5. These are the outcomes of getting 1, 3, also 3, 1, and 2, 2.
Making it a total of 3 possible outcomes.
So, the probability that the sum of the two numbers rolled is greater than 3, given that the sum of the numbers is not greater than 5, is
[tex]\begin{gathered} \frac{3}{36} \\ =\frac{1}{12} \end{gathered}[/tex]