Here,
The points are given as
[tex](-4,4)\text{ and (-2,2)}[/tex]
Using the mid-point formulla, the mid points for the given problem can be calculated as,
[tex]\begin{gathered} x=\frac{-4+(-2)}{2} \\ x=\frac{-4-2}{2} \\ x=\frac{-6}{2} \\ x=-3 \end{gathered}[/tex]
similarly,
[tex]\begin{gathered} y=\frac{4+2}{2} \\ y=\frac{6}{2} \\ y=3 \end{gathered}[/tex]
Hence, the mid point's coordinate for the given problem are
[tex](x,y)=(-3,3)[/tex]
