Given
Position of a particle
[tex]x(t)=5.66-2.41t[/tex]Procedure
First, let's calculate the position at t = 3
[tex]\begin{gathered} x(3)=5.66-2.41\cdot3 \\ x(3)=-1.57\text{ m} \end{gathered}[/tex]Now let's calculate the position t = 6
[tex]\begin{gathered} x(6)=5.66-2.41\cdot6 \\ x(6)=-8.8\text{ m} \end{gathered}[/tex]Let's calculate the displacement.
[tex]\begin{gathered} \Delta x=x(6)-x(3)=-8.8-(-1.57) \\ \Delta x=-7.23 \end{gathered}[/tex]The total displacement is -7.23 m
