Given:-
Spinner that is equally divided into four parts and then you spin it again. 1 part is red, 1 part is green, and 2 parts are blue.
To find the probability the spinner stopping on red section on the first spin and then a blue section on the second spin?
So here the sample space is the total probability of the chances. So we get,
[tex]n(s)=4[/tex]So probability of getting red, we have only 2 red parts. so we have,
[tex]n(r)=2[/tex]So the probability is,
[tex]p(r)=\frac{n(r)}{n(s)}=\frac{2}{4}=\frac{1}{2}[/tex]So the probability is,
[tex]\frac{1}{2}[/tex]So the probability of getting blue is,
[tex]n(b)=2[/tex]So the probability is,
[tex]p(b)=\frac{n(b)}{n(s)}=\frac{2}{4}=\frac{1}{2}[/tex]So the probability is,
[tex]\frac{1}{2}[/tex]