Solution
Given
[tex]125-27w^3[/tex]Recall that
[tex](a^3-b^3)=(a-b)(a^2+ab+b^2)[/tex]Therefore,
[tex]\begin{gathered} 125-27w^3=(5)^3-(3w)^3 \\ \\ \text{ |et }a=5,b=3w \\ \\ \Rightarrow(5)^3-(3w)^3=(5-3w)((5)^2+(5)(3w)+(3w)^2) \\ \\ =(5-3w)(25+15w+9w^2) \end{gathered}[/tex]