Since the first row has 4 cans, the second has 8 and the third has 12, we can write the following sequence:
[tex]4,8,12,\ldots[/tex]notice that the common difference in this sequences is d = 4. Then, we can use the formula to find the expression of the sequence:
[tex]\begin{gathered} a_n=a_1+(n-1)d \\ a_1=4 \\ d=4 \\ \Rightarrow a_n=4+(n-1)(4)=4+4n-4=4n \\ a_n=4n \end{gathered}[/tex]then, on the bottom row, we have that n = 12, then:
[tex]a_{12}=4(12)=48[/tex]therefore, there are 48 cans in the bottom row