Experiment 3, you need to prepare a 30 mL solution of a 1:6 syrup solution.You have on hand a 50% syrup solution, and a 1:200 soda solution.How many mLs of soda solution do you need to create this final solution?How many mLs of syrup solution do you need to create this final solution?

Respuesta :

Given:

Total solution = 30 ml

The final solution ratio is 1 part syrup to 6 parts soda.

50% syrup solution.

1:200 soda solution.

Find-: How many soda solutions need to create the final sol.

Sol:

Let x = Number of liter of the 50% syrup solution.

y = Number of a liter of the 1 parts syrup to 200 parts soda solution.

So,

[tex]x+y=30[/tex]

1:200 soda solution and 50% syrup.

[tex]\frac{1}{2}x+\frac{1}{201}y=\frac{1}{7}\times30[/tex]

Solve for "x" and "y" the put

[tex]y=30-x[/tex][tex]\begin{gathered} \frac{1}{2}x+\frac{1}{201}(30-x)=\frac{1}{7}\times30 \\ \\ x=8.356 \end{gathered}[/tex]

Then the value of "y" is:

[tex]\begin{gathered} y=30-x \\ \\ y=21.644 \end{gathered}[/tex]

Final sol. will be 30 ml total,

It will contain 8.356 ml of 50% syrup solution.

it will contain 21.644 ml of 1 part syrup to 200 parts soda solution

For the total amount of syrup in the final solution.

[tex]\begin{gathered} \frac{1}{2}(8.356)+\frac{1}{201}(21.644) \\ \\ =4.286 \end{gathered}[/tex]

4.286 ml of pure syrup