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Three point charges are located along the x-axis: q1 = +5.0 μC is at 20 cm, q2 = +4.0 μC is at 0 cm, and q3 = +10.0 μC is at –30 cm. What is the electrostatic force exerted on q2 by q1?

Respuesta :

Given,

The charges are:

[tex]q_1=5.0\mu C\text{ at x=20 }cm[/tex][tex]q_2=4.0\mu C\text{ at x=0 }cm[/tex][tex]q_3=10\mu C\text{ at x=-30 }cm[/tex]

The distancce between q1 and q2 is 20 cm

Thus,

The force on q2 due to q1 is:

[tex]F=k\frac{5\times4}{20^2}=8.9\times10^9\times\frac{20}{20^2}=0.00045C[/tex]

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