The recursive formula is:
[tex]A(n)=-9+(n-1)(6)[/tex]Where n is the n'th term
Third term:
Put n = 3, so we have:
[tex]\begin{gathered} A(3)=-9+(3-1)(6) \\ =-9+(2)(6) \\ =3 \end{gathered}[/tex]Thirteenth term:
Put n = 13, so we have:
[tex]\begin{gathered} A(13)=-9+(13-1)(6) \\ =-9+(12)(6) \\ =63 \end{gathered}[/tex]