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To rent a certain meeting room, a college charges a reservation fee of $44 and an additional fee of $6.40 per hour. The math club wants to spend less thanS95.20 on renting the meeting room.What are the possible amounts of time for which they could rent the meeting room?Use 1 for the number of hours the meeting room is rented, and solve your inequality for t.

Respuesta :

cost of renting a meeting room = reservation fee + additional fee per hour,

Therefore,

[tex]C=44+6.40*t[/tex]

where,

C is the total cost and,

t is time in hours

Since, the math club wants to spend less than $95.20, then C < $95.20

Therefore,

[tex]44+6.40t<95.20[/tex]

Now, let's solve the inequality above for t,

1. substract 44 from both sides

[tex]\begin{gathered} 44+6.40t-44<95.20-44 \\ 6.40t<51.20 \end{gathered}[/tex]

2. divide both sides by 6.40

[tex]\begin{gathered} \frac{6.40t}{6.40}<\frac{51.20}{6.40} \\ t<8 \end{gathered}[/tex]

Thus, they can only rent the meeting room for up to 8 hours

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