Calculate the current produced for an electroscope with a surplus of 2.2 x1010 electrons that discharge in 0.60 s through a person's finger.

Respuesta :

Given,

The number of electrons discharged, N=2.2×10¹⁰

The time duration, t=0.60 s

The charge of one electron is e=1.6×10⁻¹⁹ C

Thus the total charge discharged due to N numbers of electrons is,

[tex]\begin{gathered} q=Ne \\ =2.2\times10^{10}\times1.6\times10^{-19} \\ =3.52\times10^{-9}\text{ C} \end{gathered}[/tex]

The electric current can be described as the time rate of flow of the charges.

Thus the current produced for an electroscope is given by,

[tex]I=\frac{q}{t}[/tex]

On substituting the known values,

[tex]\begin{gathered} I=\frac{3.52\times10^{-9}}{0.60} \\ =5.87\times10^{-9}\text{ A} \end{gathered}[/tex]

Thus the current produced is 5.87×10⁻⁹ A