Given,
The number of electrons discharged, N=2.2×10¹⁰
The time duration, t=0.60 s
The charge of one electron is e=1.6×10⁻¹⁹ C
Thus the total charge discharged due to N numbers of electrons is,
[tex]\begin{gathered} q=Ne \\ =2.2\times10^{10}\times1.6\times10^{-19} \\ =3.52\times10^{-9}\text{ C} \end{gathered}[/tex]The electric current can be described as the time rate of flow of the charges.
Thus the current produced for an electroscope is given by,
[tex]I=\frac{q}{t}[/tex]On substituting the known values,
[tex]\begin{gathered} I=\frac{3.52\times10^{-9}}{0.60} \\ =5.87\times10^{-9}\text{ A} \end{gathered}[/tex]Thus the current produced is 5.87×10⁻⁹ A