Given data:
*The initial velocity of an object is v_0 = 10 m/s
*The given acceleration is a = 3.5 m/s^2
*The given time is t = 8 s
The formula for the distance traveled during the time is given by the equation of motion as
[tex]x=x_0+v_0t+\frac{1}{2}at^2[/tex]*Here x_0 = 0 m is the initial position of the particle
Substitute the known values in the above expression as
[tex]\begin{gathered} x=(0)+(10)(8)+\frac{1}{2}(3.5)(8)^2 \\ =80+112 \\ =192\text{ m} \end{gathered}[/tex]Hence, the distance traveled during the time is x = 192 m
