Given:
There are given that inequality:
[tex]-36\leq2x+4(x-3)[/tex]
Explanation:
According to the question:
We need to solve the above-given inequality:
[tex]\begin{gathered} -36\leqslant2x+4(x-3) \\ -36\leqslant2x+4x-12 \end{gathered}[/tex]
Then,
[tex]\begin{gathered} -36\leqslant2x+4x-12 \\ -36\leqslant6x-12 \end{gathered}[/tex]
Then,
[tex]6x-12\ge-36[/tex]
Then,
Add 12 on both sides of the equation:
[tex]\begin{gathered} 6x-12\geqslant-36 \\ 6x-12+12\geqslant-36+12 \\ 6x\ge-24 \end{gathered}[/tex]
Then,
Divide by 6 on both sides of the equation:
So,
[tex]\begin{gathered} 6x\geqslant-24 \\ \frac{6x}{6}\geqslant\frac{-24}{6} \\ x\ge-4 \end{gathered}[/tex]
We can see that the value of x is greater than and equal to -4.
Final answer:
Hence, the correct option is B.
