Respuesta :
Given data:
* The height of the hill is h_i = 20 meters.
* The length of the hill is L = 80 meters.
* The mass of the pig is m = 300 kg.
* The initial velocity of the pig is u = 0 m/s.
* The final height of the pig is h_f = 0 meters.
Solution:
The net energy of the system at the top of the hill is,
[tex]E_i=mgh_i+\frac{1}{2}mu^2[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} E_i=300\times9.8\times20+0 \\ E_i=58800\text{ J} \end{gathered}[/tex]The net energy of the system at the bottom of the hill is,
[tex]E_f=\text{mgh}_f+\frac{1}{2}mv^2[/tex]where v is the final velocity of the pig,
Substituting the known values,
[tex]\begin{gathered} E_f=0+\frac{1}{2}\times300\times v^2 \\ E_f=150v^2 \end{gathered}[/tex]According to the law of conservation of energy,
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