we have the equation
[tex]L=x+y+\frac{1}{2}T[/tex]we have
x=5 1/4 in=5+1/4=21/4 in
y=13 7/8 in=13+7/8=111/8 in
T=1/4 in
substitute the given values in the expression above
[tex]L=\frac{21}{4}+\frac{111}{8}+\frac{1}{2}(\frac{1}{4})[/tex][tex]L=\frac{21}{4}+\frac{111}{8}+\frac{1}{8}[/tex]Remember that
21/4 is equivalent to 42/8
substitute
[tex]L=\frac{42}{8}+\frac{111}{8}+\frac{1}{8}=\frac{42+111+1}{8}=\frac{154}{8}=19.25=19\frac{1}{4}in[/tex]the answer is
