Can someone help me Using the trigonometric ratios, solve for the missing sides x and y of each right triangle. Round your answers to the nearest tenth.

Given,
The measue of one side is 19.
The measure of one angle is 80 degree.
Required
The value of x and y.
a)By trigonometric ratio,
[tex]\begin{gathered} sin80^{\circ}=\frac{19}{x} \\ x=\frac{19}{sin80^{\circ}} \\ x=19.3 \end{gathered}[/tex]The value of y is calculatedby using cosine,
[tex]\begin{gathered} cos80^{\circ}=\frac{y}{19.29} \\ y=cos80^{\circ}\times19.29 \\ y=3.4 \end{gathered}[/tex]Hence, the value of x is 19.3 and y is 3.4.
b)By trigonometric ratio,
[tex]\begin{gathered} sin45^{\circ}=\frac{y}{27} \\ y=sin45^{\circ}\times27 \\ y=19.1 \end{gathered}[/tex]The value of x is calculatedby using cosine,
[tex]\begin{gathered} cos45^{\circ}=\frac{x}{27} \\ x=cos45^{\circ}\times27 \\ x=19.1 \end{gathered}[/tex]Hence, the value of x is 19.1 and y is 19.1.