Can someone help me Using the trigonometric ratios, solve for the missing sides x and y of each right triangle. Round your answers to the nearest tenth.

Can someone help me Using the trigonometric ratios solve for the missing sides x and y of each right triangle Round your answers to the nearest tenth class=

Respuesta :

Given,

The measue of one side is 19.

The measure of one angle is 80 degree.

Required

The value of x and y.

a)By trigonometric ratio,

[tex]\begin{gathered} sin80^{\circ}=\frac{19}{x} \\ x=\frac{19}{sin80^{\circ}} \\ x=19.3 \end{gathered}[/tex]

The value of y is calculatedby using cosine,

[tex]\begin{gathered} cos80^{\circ}=\frac{y}{19.29} \\ y=cos80^{\circ}\times19.29 \\ y=3.4 \end{gathered}[/tex]

Hence, the value of x is 19.3 and y is 3.4.

b)By trigonometric ratio,

[tex]\begin{gathered} sin45^{\circ}=\frac{y}{27} \\ y=sin45^{\circ}\times27 \\ y=19.1 \end{gathered}[/tex]

The value of x is calculatedby using cosine,

[tex]\begin{gathered} cos45^{\circ}=\frac{x}{27} \\ x=cos45^{\circ}\times27 \\ x=19.1 \end{gathered}[/tex]

Hence, the value of x is 19.1 and y is 19.1.