Can someone help me with this geometry question?The first box has three options: 20,30,40, the second box has 24,48,18

Explanation:
First, find the area of the lampshade.
The lampshade is in the shape of a trapezoid; the area of a trapezoid is calculated using the formula:
[tex]\begin{gathered} A=\frac{1}{2}(a+b)h \\ a,b\text{ are the parallel sides} \\ h\text{ is the perpendicular height} \end{gathered}[/tex]Thus, the area of the lampshade is approximately:
[tex]A=\frac{1}{2}(7+4)6=11\times3=33\approx30\; in.^2[/tex]Next, we find the area of the base.
The base is made up of two trapezoids and the area of one of the trapezoids is approximately:
[tex]A=\frac{1}{2}(3+6)\times\frac{8}{2}=\frac{1}{2}\times9\times4=18\; in\text{.}^2[/tex]Thus, the total area is approximately:
[tex]\text{Total Area}=30+2(18)=30+36\approx66\; in\text{.}^2[/tex]Therefore:
Answer:
• The lampshade is a trapezoid. Its area is approximately ,30 square inches.
,• The bases of the lamp are two trapezoids. The area of each is approximately ,18 square inches,.
,• In total, the area is approximately ,66 square inches,.