Answer
The final temperature in °C = 166.6 °C.
Explanation
Given:
Initial temperature, T₁ = 20.0 °C
Initial volume, V₁ = 10.0 L
Final volume, V₂ = 15.0 L
What to find:
The final temperature in °C.
Step-by-step solution:
Since is held under isobaric conditions i.e constant pressure, the final temperature can be determined using the Charle's law equation below.
[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \\ \Rightarrow T_2=\frac{T_1V_2}{V_1} \end{gathered}[/tex]Plugging T₁ = (20.0 + 273.15) = 293.15 K, V₁ = 10.0 L and V₂ = 15.0 L into the equation, we have
[tex]T_2=\frac{293.15\text{ }K\times15.0\text{ }L}{10.0\text{ }L}=439.725K[/tex]The final step is to convert the temperature from Kelvin to °C.
The final temperature = (439.725 - 273.15) = 166.6 °C.
