Respuesta :
Answer: the volume of the gas under the conditions given is 7.80 L
Explanation:
The question requires us to determine the volume of a gas that contains 0.323 mol and is at 265 K and 0.900 atm.
We can apply the equation of ideal gases to solve this problem, as shown below:
[tex]P\times V=n\times R\times T[/tex]where P is the pressure of the gas (0.900 atm), V is the volume we want to calculate, n is the number of moles of gas (0.323 mol), R is the constant of gases and T is the temperature (265 K).
We can rearrange the equation to calculate the volume of the gas:
[tex]PV=nRT\rightarrow V=\frac{n\times R\times T}{P}[/tex]Since the pressure was given in atm and the temperature in K, we can use the following value for the constant of gases:
[tex]R=0.082057\frac{L.atm}{mol.K}[/tex]Note that the volume will be obtained in liters (L).
Applying the values provided by the question, we'll have:
[tex]\begin{gathered} \begin{equation*} V=\frac{n\times R\times T}{P} \end{equation*} \\ \\ V=\frac{(0.323\text{ mol\rparen}\times(0.082057\text{ L.atm/mol.K\rparen}\times(265\text{ K\rparen}}{(0.900\text{ atm\rparen}}=7.80\text{ L} \end{gathered}[/tex]Therefore, the volume of the gas under the conditions given is 7.80 L.
