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Linda evaluates the expression 7+5x for x=3 and x+4/5. When x=3, she gets 7+5x=7+5 times 3 =12 times 3 =36. When x=4/5, she gets 7+5x=7+5 times 4/5=12 times 4/5=48/5. What does linda do wrong?Explain

Respuesta :

the first expression

[tex]7+5x[/tex]

x=3

[tex]7+5(3)=7+15=22[/tex]

she was wrong because she first sum 7+5 and she doesn't respect that first we always solve the brackets and then the other operations

and for x=4/5

[tex]7+5(\frac{4}{5})=7+4=11[/tex]

the same mistake she doesn't respect that first we always solve the operations with brackets and then the other operations

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