Respuesta :

Notice that:

[tex]\begin{gathered} 6x+3(y+4)=27 \\ 3\cdot2x+3\cdot y+3\cdot4=27 \\ 3(2x+y)=27-12 \\ 3(2x+y)=15 \end{gathered}[/tex]

Solving for 2x+y we get:

[tex]\begin{gathered} \\ 2x+y=\frac{15}{3} \\ 2x+y=5 \end{gathered}[/tex]

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