From the given figure
The number of students who prefer Chocolate is 7
The number of students who prefer Vanilla is 11
The number of students who prefer Strawberries is 3
The number of students who prefer Cookies and cream is 4
Then the total number of students in the survey is
[tex]\begin{gathered} N=7+11+3+4 \\ N=25 \end{gathered}[/tex]
Since the probability = faverate/total, then
The probabilities of each item are
[tex]\begin{gathered} P\left(Ch\right)=\frac{7}{25} \\ \\ P\left(V\right)=\frac{11}{25} \\ \\ P\left(S\right)=\frac{3}{25} \\ \\ P\lparen C\text{ \&C\rparen=}\frac{4}{25} \end{gathered}[/tex]
Let us find the correct answer
A.
Chocolate and cream has 4 students which are not the least popular flavor
The least popular flavor is the strawberry
Answer A is wrong
B.
The number of students who prefer strawberry = 3
The number of students who prefer cookies and cream = 4
3 is not half 4, then
Answer B is wrong
C.
The number of students who prefer chocolate = 7
The number of students who prefer strawberry and who prefer cookies and cream = 3 + 4 = 7
Then they are the same
Answer C is correct
D.
The number of students who prefer vanilla = 11
The number of students who prefer either chocolate or strawberry = 7 + 3 = 10
11 is not less than 10, then
Answer D is wrong
The correct answer is C
