Solution:
Given:
Part A:
To complete the rectangle, the coordinate of the fourth vertex will be (7,9).
Part B:
The length of the rectangle is 7 - 2 = 5 units
The with of the rectangle is 9 -2 2 = 7 units
Hence, the perimeter is gotten using the formula;
[tex]\begin{gathered} P=2(l+w) \\ l=5 \\ w=7 \\ \\ P=2(5+7) \\ P=2(12) \\ P=2\times12 \\ P=24units \end{gathered}[/tex]
Therefore, the perimeter of the rectangle is 24 nits.
