What would I set the scales to also what would be the vertex,roots , and two other points

We have
[tex]y=-x^2-22x-112[/tex]For the vertex we have the next formula
for the x-coordinate of the vertex
[tex]x=\frac{-b}{2a}[/tex]In our case
a=-1
b=-22
[tex]x=\frac{22}{2(-1)}=-11[/tex]then we substitute this value in the function
[tex]y=-(-11)^2-22(-11)-112=9[/tex]The vertex is (-11,9)
For the roots we make y=0
[tex]\begin{gathered} -x^2-22x-112=0 \\ x^2+22+112=0 \end{gathered}[/tex]Then we factorize
[tex](x+14)(x+8)=0[/tex]The roots are
x=-14
x=-8
Then for other two points
x=-15
[tex]-(-15)^2-22(-15)-112=-7[/tex]Point (-15,7)
x=-7
[tex]-(-7)^2-22(-7)-112=-7[/tex]Point (-7,-7)
the x-sel1
the ysel : 2